Sorry can´t follow you:
OK Ohm's law: I=V/R=1mV/100k=0.01µA
R total = (R1*R2)/(R1+R2)= (100k*100k)/(100k+100k) = 50K
Ohm's law: V= 0,01µA*50K=0,5mV
Ohm's law: I=U/R so half of the resistance means double voltage
Sorry can´t follow you:
OK Ohm's law: I=V/R=1mV/100k=0.01µA
R total = (R1*R2)/(R1+R2)= (100k*100k)/(100k+100k) = 50K
Ohm's law: V= 0,01µA*50K=0,5mV
Ohm's law: I=U/R so half of the resistance means double voltage
Inspo, Hammer Head, KISS rEvo
From memory my Uri HUD I had on the Inspo Classic had a 10K resister in line which was to prevent errors in the event of a handset failure causeing reverse current.
Does that sound correct?
I know nothing about electronics
I took APDs comments to Uri Barron who designed the HUD and he said they were talking bollocks. I thaught he might be bias so I took the issue to a freind who was an electrical engener doing R&D and he agreed it was bollocks.
ATB
Mark
CCR Instructor Trainer
The problem I think is you are incorrectly assuming that the cell monitoring circuitry is what is providing the load when in fact the load for the cell is a built in resistor on the cells circuit board and the input impedance of the hand set cell monitoring hardware has minimal effect on the cells load.
Strictly speaking both the output impedance of the sensor and the input impedance of the monitor combined is what makes up the load for the fuel cell at the hearth of the sensor. So not so much an incorrect assumption as a pedagogical problem digging to deep into the details. The important part is your last sentence which is how this discussion got started and what has been my point all along; the handset monitoring hardware has minimal effect on the cell load. You are the second person here to agree on that. That means that connecting a second monitoring device to a cell will not screw up its readings nor will it make them dependent on each other.
Last edited by Tastyfish; 1st June 2014 at 18:15.