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Equivalent Air Density Depth (EADD)



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Old 2nd December 2005, 12:39   #11 (permalink)
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Re: Equivalent Air Density Depth (EADD)

An additional question which may be completely irrelevant, or not - but here goes :

Is the viscosity of the gases significant to take into account - and if so, then you might need to consider the temperature of the gas that you use. After all if a 10deg C change makes water half as viscous, then I would assume that it has at least some effect on other fluids. Unfortunately I can't add much more than that, but perhaps someone else can take up the baton?

cheers

Ed
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Old 5th December 2005, 11:46   #12 (permalink)
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Re: Equivalent Air Density Depth (EADD)

Quote: (Originally Posted by koputai)
Seems like a good time to rehash this:
http://www.deepdiving.net/rants/norcotic.html

Just use norcotic trimix Steve.

Jason.
Excellent concept. Heres an additional twist.

Daltons law states that the pressure of a gas mixture is the sum of the partial pressures of the component gases.
Henry's law states that the solubility of a gas is directly proportional to its pressure.

If we use trimix 10/70/20 at 90m the ppO2 = 1bar, ppHe = 7 bar, ppN2 = 2 bar right?

Henrys law states the gas dissolved in the liquid is proportional to these individual pressures, so O2 gets metabolised and isn't a primary concern, He dissolves to the tune of 7 bar x time, N2 dissolves to the tune of 2 bar x time.
If we vary these individual pressures by changing the mix we will vary the "driver" that causes the gas to dissolve?
I generally use nitrogen at max 20% because it is manageable narcotically and from a density WOB point of view on deep dives, plus it means the helium is not so close to saturation as it would be if I used "norcotic trimix", so in principle I am less saturated with He.
Too much N2 means bends, narcs and high WOB.
Too much He means bigger risk of a He bend and the willies.
Adjust the proportions for optimum effect.

With me in principle? here comes the twist.
IF it were possible to use 10 different inert gases! (decamix?) each one at say 10%, none of the individual gases would exceed a pp over 1 bar at 90m and the "driver" which causes them to dissolve, would be substantially reduced, - maybe to a "no stop" saturation level !!!
IF this were possible could decompression be avoided altogether ?!?
Unfortunately there aren't enough inert gases with the appropriate properties for a diluent.
Quadmix maybe??
Gives yer brain a workout doesn't it?
Tim
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Old 5th December 2005, 20:14   #13 (permalink)
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Re: Equivalent Air Density Depth (EADD)

Quote: (Originally Posted by Tim Cashman)
IF it were possible to use 10 different inert gases! (decamix?) each one at say 10%, none of the individual gases would exceed a pp over 1 bar at 90m and the "driver" which causes them to dissolve, would be substantially reduced, - maybe to a "no stop" saturation level !!!
IF this were possible could decompression be avoided altogether ?!?
Unfortunately there aren't enough inert gases with the appropriate properties for a diluent.
Quadmix maybe??
Gives yer brain a workout doesn't it?
Tim
Gidday Tim, long time no hear!!

Sorry to rain on your parade but applying your own excellent explanation of Dalton's law, you will appreciate that at the end of a dive with your ten gases, the total pressure of gas in a tissue will equal the sum of the partial pressures.

For a bubble to grow, the following condition must be satisfied:

Ptiss > Pamb + ((2 x surface tension) / bubble radius)

Where: Ptiss = total gas pressure in the tissue
Pamb = ambient pressure

Since Ptiss includes the sum of partial pressures of all inert gases in the tissue, it doesn't matter if you have created a situation where the partial pressures of the individual gases are low by breathing 10 gases. If you add them together and Ptiss satisfies the above condition then you are no further ahead.

Good to see you around here.

Warm regards,

Simon M

Last edited by Simon Mitchell : 5th December 2005 at 23:19.
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Old 5th December 2005, 20:20   #14 (permalink)
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Re: Equivalent Air Density Depth (EADD)

Hi Tim,
Interesting theory. You first


I'm, at heart, skeptical about the free lunch this idea suggests might be on offer and I have the feeling that there might be some cummulative effect on vapour pressure in tissues and hence your bubbles will just have 4 different inert gasses instead of the usual two. If this is not right maybe your idea has merit?

Cheers.
AB


Edit: Ahh, there you go...thanks Doc.
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Old 7th December 2005, 21:04   #15 (permalink)
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Re: Equivalent Air Density Depth (EADD) - "Multimix"

Hi Simon Howzitgoin?
(Read Keiths book Deep Water Gold? He did a good job of it. Your on pages 182 and 229!)

Re "Multimix"
I'm sure you're right or someone would have used this concept by now.
The concept is purely the physics of gases dissolving in liquids and what drives it.

Henry's Law was the twist.
Each component gas goes in or out of solution in proportion to the pp of itself vs the saturation of itself?
ie it goes in and out of solution independently of its neighbours?

I was theorising if there was an ideal balance of gases what could it be?

I take your point though, that if there is a 10 ata ambient and 10 gases all at pp of 1 bar you still get 10 bar total and what goes in must come out again.
10 bar in = 10 bar out later; irrespective of whether it is a multiple gas mix or a single gas.

Pub!

Tim
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Last edited by Tim Cashman : 7th December 2005 at 21:25.
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Old 7th December 2005, 22:23   #16 (permalink)
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Re: Equivalent Air Density Depth (EADD) - "Multimix"

Quote: (Originally Posted by Tim Cashman)

Pub!

Tim
Mate!

The smartest thing I've read on any forum for ages!

Simon
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Old 4th July 2007, 09:27   #17 (permalink)
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Re: Equivalent Air Density Depth (EADD)

Quote: (Originally Posted by Steve) View Original Post
In this thread http://www.rebreatherworld.com/technical-rebreather-forum/2289-new-v-planner-3-70-a.html I asked Ross if he could include and EADD calculation into V-Planner. Ross has PMed me and thinks the idea has some merit.

OK here is the bit about my bright idea I just don’t know much about. How deep an EADD is too deep? I think it’s important to at least be aware of this as breathing too dense a mix at depth can easily predispose one to CO2 accumulation. Gas selection is not just about ppO2 and narcosis. A figure indicating the equivalent resistance of breathing air when diving very deep dives would be handy to know.

What is a meaningful number?

To save you reading the other thread here is a bit of a cut and paste to summarise what I’m on about.

I’m after a feature that provides an Equivalent Air Density Depth (EADD) ie breathing 5/80 @ 150m is like breathing air @ 'x' m

This would be of particular use for very deep dives when factoring in gas breathability V's EAD V's CNS V's Deco considerations

As far as I know (please don't hold me to this) its a straight forward case of gas % x gas density at STP x pressure at depth = density at depth
Density of individual gases in kgs/m3 at STP is
O2 1.429
N2 1.250
He 0.179
CO2 1.977

eg density of air at 40m (O2 + N2)
(1.429 x 21% x 5ata) + (1.250 x 79% x 5ata) = 6.438 kgs/m3

eg 2 density of trimix 5/80 at 200m (O2 + He + N2)
(1.429 x 5% x 21ata) + ( 0.179 x 80% x 21ata) + ( 1.250 x 15% x 21ata) =8.4375 kgs/m3

Which gives an EADD of 58m

Might be due to ignorance, however the transition from 8.4375Kgs/m3 to 58 meters is something in my theoretical education that has become lost. Is it possible to have the transition explained as well?
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Old 4th July 2007, 10:50   #18 (permalink)
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Re: Equivalent Air Density Depth (EADD)

(1.429 * 21% * xata) + ( 1.250 * 79% * xata) =8.4375 kgs/m3
-> .3009*x ata + .9875* x ata = 8.4375
-> (.3009+ .9875) * x ata = 8.4375
-> 1.2884 * x ata= 8.4375
-> x ata = 8.4375/1.2884
-> x ata = 6.576
D(m)= (D(ata)*10)-10
-> x (m) = (6.576*10)-10
-> x (m) = ~56

i suspect some rounding errors to account for the difference.

"state of origin" rugby league here tonight so lots of piss being drunk
rachel

GO QUEENSLAND!

.....OR
This would have been easier to type and quicker to work out:
GIVEN (1.429 * 21% * 5ata) + ( 1.250 * 79% * 5ata) =6.438 kgs/m3
AND (1.429 * 21% * xata) + ( 1.250 * 79% * xata) =8.4375 kgs/m3
the equation becomes a ratio.
-> x ata= 8.4375/6.438 * 5 ata
-> x ata = 6.552
-> x m =~56m
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Last edited by bendomatic : 4th July 2007 at 20:49.
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