Rebreather World - View Single Post - Rate of PO2 drop changes with depth true/false

bhackett · 25th December 2006, 03:32

Quote: (Originally Posted by Genesis)

We arrive at 5 ATA and wish to operate with the same .20 PO2 (I know, that's stupid, but the math is easier if we leave it alone.)

So we now have 5 times the moles of gas in the loop, although the volume is the same. That is, we have 10 liters of O2 (at STP) in the loop and 40 liters (at STP) of diluent. Since the gas is at 5 ATA it occupies 10 liters, not the 50 it would occupy on the surface.

Uh, 10 liters of O2 would be 20%, not .2 PO2.

.2 PO2 / 5ata = .04 FO2. .04 FO2 * 50 liters = 2 liters O2.

Brian

25th December 2006, 03:32	#6 (permalink)
bhackett New Member Current Rebreather/s: Sport Kiss Other Rebreather/s: Join Date: Apr 2005 Location: San Francisco, CA Posts: 11	Re: why do we do it? Quote: (Originally Posted by Genesis) We arrive at 5 ATA and wish to operate with the same .20 PO2 (I know, that's stupid, but the math is easier if we leave it alone.) So we now have 5 times the moles of gas in the loop, although the volume is the same. That is, we have 10 liters of O2 (at STP) in the loop and 40 liters (at STP) of diluent. Since the gas is at 5 ATA it occupies 10 liters, not the 50 it would occupy on the surface. Uh, 10 liters of O2 would be 20%, not .2 PO2. .2 PO2 / 5ata = .04 FO2. .04 FO2 * 50 liters = 2 liters O2. Brian
(Offline)