| Re: why do we do it? At 10m, pressure 2atm:
PO2=1.3
FiO2 = 1.3/2 = 0.65 ie 65%O2
For example total loop volume is 10 litres, therefore oxygen content of loop is 10x0.65x2 (x2 to convert to surface-equivalent litres ie mass). =13 litres O2
At 110m, pressure 12atm:
PO2=1.3
FiO2 = 1.3/12 = 0.10833333
With same 10 litre loop volume, O2 content, adjusted to surface is:
10x0.10833333x12 =13 litres O2
Therefore the mass of O2 is the same in both examples, so given the same oxygen consumption your PO2 will decline at the same rate at whatever depth.
If I am missing something please tell me, if not then a potentially dangerous myth is being promoted.
Neil
__________________ Never forget that life is a finite resource. |